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How do you differentiate #f(x)=e^(x^3-x^2-4) # using the chain rule?

1 Answer

Jan 1, 2016

I found: #y=(3x^2-2x)e^(x^3-x^2-4)#

Explanation:

First you derive #e# alone as it is and then multiply by the derivative of the exponent (in red):
#y=e^(x^3-x^2-4)*[color(red)(3x^2-2x)]#

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