How do you differentiate #f(x)=e^(5x^2+7x-13)#? Calculus Basic Differentiation Rules Chain Rule 1 Answer turksvids Nov 29, 2017 #f'(x) = e^(5x^2+7x-13)*(10x+7)# Explanation: By the Chain Rule, #d/dx(e^u)=e^u*(du)/dx# Let #u=5x^2+7x-13# so #(du)/dx = 10x+7# so the derivative works out to #f'(x) = e^(5x^2+7x-13)*(10x+7)#. Answer link Related questions What is the Chain Rule for derivatives? How do you find the derivative of #y= 6cos(x^2)# ? How do you find the derivative of #y=6 cos(x^3+3)# ? How do you find the derivative of #y=e^(x^2)# ? How do you find the derivative of #y=ln(sin(x))# ? How do you find the derivative of #y=ln(e^x+3)# ? How do you find the derivative of #y=tan(5x)# ? How do you find the derivative of #y= (4x-x^2)^10# ? How do you find the derivative of #y= (x^2+3x+5)^(1/4)# ? How do you find the derivative of #y= ((1+x)/(1-x))^3# ? See all questions in Chain Rule Impact of this question 3200 views around the world You can reuse this answer Creative Commons License