How do you differentiate f(x)=csc(sqrt(e^x)) f(x)=csc(√ex) using the chain rule?
1 Answer
Jan 5, 2016
Explanation:
Use the chain rule (a lot of times!):
First issue: the cosecant function:
f'(x)=-csc(sqrt(e^x))cot(sqrt(e^x))*d/dx(sqrt(e^x))
Second issue: the square root:
f'(x)=-csc(sqrt(e^x))cot(sqrt(e^x))*1/2(e^x)^(-1/2)*d/dx(e^x)
Here, recall that
f'(x)=-csc(sqrt(e^x))cot(sqrt(e^x))*1/2(e^x)^(-1/2)*e^x
To multiply
f'(x)=(-sqrt(e^x)csc(sqrt(e^x))cot(sqrt(e^x)))/2