How do you differentiate #f(x)=csc(1/(5x^2-1))# using the chain rule? Calculus Basic Differentiation Rules Chain Rule 1 Answer Trevor Ryan. Dec 14, 2015 #d/dxcsc(1/(5x^2-1))=-csc(1/(5x^2-1))*cot(1/(5x^2-1))*(-10x)/(5x^2-1)^2# Explanation: #d/dxcsc(1/(5x^2-1))=-csc(1/(5x^2-1))*cot(1/(5x^2-1))*(-10x)/(5x^2-1)^2# Answer link Related questions What is the Chain Rule for derivatives? How do you find the derivative of #y= 6cos(x^2)# ? How do you find the derivative of #y=6 cos(x^3+3)# ? How do you find the derivative of #y=e^(x^2)# ? How do you find the derivative of #y=ln(sin(x))# ? How do you find the derivative of #y=ln(e^x+3)# ? How do you find the derivative of #y=tan(5x)# ? How do you find the derivative of #y= (4x-x^2)^10# ? How do you find the derivative of #y= (x^2+3x+5)^(1/4)# ? How do you find the derivative of #y= ((1+x)/(1-x))^3# ? See all questions in Chain Rule Impact of this question 1610 views around the world You can reuse this answer Creative Commons License