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How do you differentiate #f(x)=cos(-3x^2+2)^2#?

1 Answer

Oct 31, 2016

#f'(x)=12x(-3x^2+2) sin(-3x^2+2)^2#

Explanation:

#f(x)=cos(-3x^2+2)^2#

#f'(x)=-sin(-3x^2+2)^2 * 2(-3x^2+2) *-6x#

#f'(x)=12x(-3x^2+2) sin(-3x^2+2)^2#

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