How do you differentiate #f(x)=(cos^2x^2)^(7/3)# using the chain rule? Calculus Basic Differentiation Rules Chain Rule 1 Answer Alan N. Sep 12, 2016 #-28/3xcos^(11/3)(x^2)sin(x^2)# Explanation: #f(x) = (cos^2x^2)^(7/3)# #=(cos^(14/3)x^2)# #f'(x) = 14/3* cos^(11/3)x^2 * d/dx(cosx^2)# (Power rule and Chain rule) #= 14/3* cos^(11/3)x^2 * (-sinx^2) * 2x# (Chain rule) #=-28/3xcos^(11/3)(x^2)sin(x^2)# Answer link Related questions What is the Chain Rule for derivatives? How do you find the derivative of #y= 6cos(x^2)# ? How do you find the derivative of #y=6 cos(x^3+3)# ? How do you find the derivative of #y=e^(x^2)# ? How do you find the derivative of #y=ln(sin(x))# ? How do you find the derivative of #y=ln(e^x+3)# ? How do you find the derivative of #y=tan(5x)# ? How do you find the derivative of #y= (4x-x^2)^10# ? How do you find the derivative of #y= (x^2+3x+5)^(1/4)# ? How do you find the derivative of #y= ((1+x)/(1-x))^3# ? See all questions in Chain Rule Impact of this question 1354 views around the world You can reuse this answer Creative Commons License