How do you differentiate #f(x) = 5(2x-3)^(3/2) # using the chain rule? Calculus Basic Differentiation Rules Chain Rule 1 Answer Michael Feb 20, 2016 You can do it like this: Explanation: #f(x)=5(2x-3)^(3/2# #:.f'(x)=5xx3/2(2x-3)^(1/2)xx(2)# #:.f'(x)=15(2x-3)^(1/2)# or #f'(x)=15sqrt(2x-3)# Answer link Related questions What is the Chain Rule for derivatives? How do you find the derivative of #y= 6cos(x^2)# ? How do you find the derivative of #y=6 cos(x^3+3)# ? How do you find the derivative of #y=e^(x^2)# ? How do you find the derivative of #y=ln(sin(x))# ? How do you find the derivative of #y=ln(e^x+3)# ? How do you find the derivative of #y=tan(5x)# ? How do you find the derivative of #y= (4x-x^2)^10# ? How do you find the derivative of #y= (x^2+3x+5)^(1/4)# ? How do you find the derivative of #y= ((1+x)/(1-x))^3# ? See all questions in Chain Rule Impact of this question 1143 views around the world You can reuse this answer Creative Commons License