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How do you differentiate #f(x)=(4x^6-3sqrt(x/(x-5)^2)+2)^2# using the chain rule?

1 Answer

Jun 23, 2018

#f'(x)=2(4*x^6-3sqrt(x/(x-5)^2)+2)*(24*x^5-3/(2*sqrt(x/(x-5)^2))((-x-5)/(x-5)^3))#

Explanation:

By the chain rule we get

#f'(x)=2(4x^6-3sqrt(x/(x-5)^2)+2)*(24*x^5-3/(2*sqrt(x/(x-5)^2))*(x-5-2x)/(x-5)^3))#

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