How do you differentiate #f(x)=(4x+1)^2(1-x)^3# using the chain rule?
1 Answer
Aug 2, 2016
#dy/dx=(4x+1)^2[-3(1-x)^2]+(1-x)^3(32x+8)#
Explanation:
Given -
#y=(4x+1)^2(1-x)^3#
#dy/dx=(4x+1)^2[3(1-x)^2(-1)]+(1-x)^3[2(4x+1)(4)]#
#dy/dx=(4x+1)^2[-3(1-x)^2]+(1-x)^3(32x+8)#
