How do you differentiate #f(x) = 4/(x+1)^2# using the chain rule?
1 Answer
Mar 23, 2016
Explanation:
Using the
#color(blue)" chain rule " #
#d/dx [f(g(x)) ] = f'(g(x)). g'(x) # Rewrite f(x)
# = 4(x + 1 )^-2 #
#rArr f'(x) = 4.-2(x + 1)^-3 .d/dx(x + 1 ) #
# = -8(x + 1 )^-3 = (-8)/(x + 1 )^3#
