Science

Math

Humanities

... and beyond

Socratic Meta
Featured Answers

Topics

How do you differentiate #f(x)=(3x^3-2x^2+5)^331#?

1 Answer

Oct 11, 2016

#(dy)/(dx)=331(9x^2-4x)(3x^3-2x^2+5)^330#

Explanation:

Using chain rule: #(dy)/(dx)=(dy)/(du)*(du)/(dx)#

In this case, #y=(3x^3-2x^2+5)^331#

Let #u=3x^3-2x^2+5#,

then #(dy)/(du)=331u^330# and #(du)/(dx)=9x^2-4x#

So #(dy)/(dx)=331u^330*(9x^2-4x)#

#=331(9x^2-4x)(3x^3-2x^2+5)^330#

Related questions

See all questions in Chain Rule

Impact of this question

1965 views around the world

You can reuse this answer
Creative Commons License