How do you differentiate # f(x)= (3x+2)^3 # using the chain rule.?

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Answer 1 · 2015-12-25T14:58:55

#f'(x)=9(3x+2)^2#

In this scenario, according to the chain rule:

#d/dx(u^3)=3u^2*(du)/dx#

Thus,

#f'(x)=3(3x+2)^2 * d/dx(3x+2)#

#=>3(3x+2)^2 * 3#

#=>9(3x+2)^2#