How do you differentiate $f (x) = {(3 x + 2)}^{3}$ $f(x)= (3x+2)^3$ using the chain rule.?

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Answer 1 · 2015-12-25T14:58:55

$f'(x)=9(3x+2)^2$

In this scenario, according to the chain rule:

$d/dx(u^3)=3u^2*(du)/dx$

Thus,

$f'(x)=3(3x+2)^2 * d/dx(3x+2)$

$=>3(3x+2)^2 * 3$

$=>9(3x+2)^2$

How do you differentiate f(x)= (3x+2)^3 f(x)=(3x+2)3 f(x)= (3x+2)^3 using the chain rule.?