How do you differentiate f(x)=2cscx+5cosx? Calculus Differentiating Trigonometric Functions Derivatives of y=sec(x), y=cot(x), y= csc(x) 1 Answer Tazwar Sikder May 20, 2017 f'(x) = - 2 csc(x) cot(x) - 5 sin(x) Explanation: We have: f(x) = 2 csc(x) + 5 cos(x) Rightarrow f'(x) = frac(d)(dx)(2 csc(x)) + frac(d)(dx)(5 cos(x)) Rightarrow f'(x) = 2 (- csc(x) cot(x)) + 5 (- sin(x)) Rightarrow f'(x) = - 2 csc(x) cot(x) - 5 sin(x) Answer link Related questions What is Derivatives of y=sec(x) ? What is the Derivative of y=sec(x^2)? What is the Derivative of y=x sec(kx)? What is the Derivative of y=sec ^ 2(x)? What is the derivative of y=4 sec ^2(x)? What is the derivative of y=ln(sec(x)+tan(x))? What is the derivative of y=sec^2(x)? What is the derivative of y=sec^2(x) + tan^2(x)? What is the derivative of y=sec^3(x)? What is the derivative of y=sec(x) tan(x)? See all questions in Derivatives of y=sec(x), y=cot(x), y= csc(x) Impact of this question 4131 views around the world You can reuse this answer Creative Commons License