How do you differentiate f(x)=(1-xe^(3x))^2f(x)=(1−xe3x)2 using the chain rule.? Calculus Basic Differentiation Rules Chain Rule 1 Answer Ratnaker Mehta Jun 12, 2016 f'(x) =-2*e^(3x)(1-x*e^(3x))(3x+1). Explanation: f(x)=(1-x*e^(3x))^2 :. f'(x)={(1-x*e^(3x))^2}' =2(1-x*e^(3x)}(1-x*e^(3x)}' =2(1-x*e^(3x)){0-(x*e^(3x))'} =-2(1-x*e^(3x))[x*{e^(3x)}'+e^(3x)(x)'] =-2(1-x*e^(3x))[x*(e^(3x))(3x)'+(e^(3x))(1)] =-2(1-x*e^(3x))(3x*e^(3x)+e^(3x)) =-2*e^(3x)(1-x*e^(3x))(3x+1). Answer link Related questions What is the Chain Rule for derivatives? How do you find the derivative of y= 6cos(x^2) ? How do you find the derivative of y=6 cos(x^3+3) ? How do you find the derivative of y=e^(x^2) ? How do you find the derivative of y=ln(sin(x)) ? How do you find the derivative of y=ln(e^x+3) ? How do you find the derivative of y=tan(5x) ? How do you find the derivative of y= (4x-x^2)^10 ? How do you find the derivative of y= (x^2+3x+5)^(1/4) ? How do you find the derivative of y= ((1+x)/(1-x))^3 ? See all questions in Chain Rule Impact of this question 1538 views around the world You can reuse this answer Creative Commons License