How do you differentiate #f(x)=1/(x-3)^2# using the chain rule? Calculus Basic Differentiation Rules Chain Rule 1 Answer Sonnhard Jun 7, 2018 #f'(x)=-2/(x-3)^3# Explanation: Writing #f(x)=(x-3)^(-2)# then we get after #(x^n)'=nx^(n-1)# #f'(x)=-2(x-3)^(-3)# Answer link Related questions What is the Chain Rule for derivatives? How do you find the derivative of #y= 6cos(x^2)# ? How do you find the derivative of #y=6 cos(x^3+3)# ? How do you find the derivative of #y=e^(x^2)# ? How do you find the derivative of #y=ln(sin(x))# ? How do you find the derivative of #y=ln(e^x+3)# ? How do you find the derivative of #y=tan(5x)# ? How do you find the derivative of #y= (4x-x^2)^10# ? How do you find the derivative of #y= (x^2+3x+5)^(1/4)# ? How do you find the derivative of #y= ((1+x)/(1-x))^3# ? See all questions in Chain Rule Impact of this question 2767 views around the world You can reuse this answer Creative Commons License