How do you differentiate #f(x)=((1/x)^2-x)# using the chain rule?

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How do you differentiate #f(x)=((1/x)^2-x)# using the chain rule?

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Answer 1 · 2017-05-23T12:34:41

#f'(x) = -2/x-1#

Explanation:

#f(x) =( (1/x)^2 -x)#

#= x^-2 -x#

NB: Although the question calls for use of the chain rule, this is not applicable in this case. The derivative may be found by applying the power rule.

#f'(x) = -2x^-1 -1#

# = -2/x-1#

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How do you differentiate #f(x)=((1/x)^2-x)# using the chain rule?

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