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How do you differentiate #f(x) = (1-3sqrt(2x^2-1))^2 # using the chain rule?

1 Answer

Nov 1, 2016

#f'(x)=(-12x(1-3sqrt(2x^2-1)))/sqrt(2x^2-1)#

Explanation:

#f(x)=(1-3sqrt(2x^2-1))^2#

#f'(x)=2(1-3sqrt(2x^2-1)) (-3)/(2sqrt(2x^2-1)) *4x #

#f'(x)=(-12x(1-3sqrt(2x^2-1)))/sqrt(2x^2-1)#

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