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How do you differentiate #f(t)=sin^2(e^(sin^2t))# using the chain rule?

1 Answer

Feb 2, 2018

#2sine^[sin^2t]##cose^[sin^2t]#

Explanation:

#sin^2[e^[sin^2t]]= [sine^[Sin^2t]]^2# so using the chain rule , we have ....

#2[sine^[sin^2t]]# times the differential within the the brackets ie......

#cos[e^[sin^2t]]# and so we get d/dt#=2sine^[sin^2t]##cose^[sin^2t]#.

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