How do you differentiate #f(t)=sin^2[e^(sin^2)t]#? Calculus Basic Differentiation Rules Chain Rule 1 Answer Massimiliano Mar 30, 2015 The answer is, using the chain rule: #f'(t)=2sine^(sin^2t) * cose^(sin^2t) * e^(sin^2t) * 2sint * cost * 1#. Answer link Related questions What is the Chain Rule for derivatives? How do you find the derivative of #y= 6cos(x^2)# ? How do you find the derivative of #y=6 cos(x^3+3)# ? How do you find the derivative of #y=e^(x^2)# ? How do you find the derivative of #y=ln(sin(x))# ? How do you find the derivative of #y=ln(e^x+3)# ? How do you find the derivative of #y=tan(5x)# ? How do you find the derivative of #y= (4x-x^2)^10# ? How do you find the derivative of #y= (x^2+3x+5)^(1/4)# ? How do you find the derivative of #y= ((1+x)/(1-x))^3# ? See all questions in Chain Rule Impact of this question 1412 views around the world You can reuse this answer Creative Commons License