# How do you differentiate f(t)=sin^2[e^(sin^2)t]?

$f ' \left(t\right) = 2 \sin {e}^{{\sin}^{2} t} \cdot \cos {e}^{{\sin}^{2} t} \cdot {e}^{{\sin}^{2} t} \cdot 2 \sin t \cdot \cos t \cdot 1$.