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How do you differentiate #e^tanx#?

1 Answer

Mar 7, 2018

#e^(tanx)*sec^2x#

Explanation:

#(1)d/(dx)(e^x)=e^x#
#(2)d/(dx)(tanx)=sec^2x#
So,
#y=e^tanxrArr(dy)/(dx)=e^(tanx)*d/(dx)(tanx),Apply(1)#
#=>(dy)/(dx)=e^(tanx)*sec^2x,Apply(2)#

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