How do you differentiate #e^(2x^2-4x) # using the chain rule?

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How do you differentiate #e^(2x^2-4x) # using the chain rule?

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Answer 1 · 2016-03-13T00:03:41

#=4(e^(2x^2-4x))(x-1)#

Explanation:

#d/(dx)(e^(2x^2-4x))=(e^(2x^2-4x))d/(dx)(2x^2-4x)#
#=(e^(2x^2-4x))(d/(dx)(2x^2)-d/(dx)(4x))#
#=(e^(2x^2-4x))(2*2x^(2-1)-4))#
#=(e^(2x^2-4x))(4x-4)#
#=4(e^(2x^2-4x))(x-1)#

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How do you differentiate #e^(2x^2-4x) # using the chain rule?

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