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How do you differentiate #e^((2-x)^2) # using the chain rule?

1 Answer

Nov 1, 2016

#y'=-2(2-x)e^((2-x)^2)#

Explanation:

#y=e^((2-x)^2)#

Use the rule
#e^u =e^u *u'#

#y'=e^((2-x)^2) 2(2-x)*-1#

#y'=-2(2-x)e^((2-x)^2)#

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