How do you differentiate #cos(x^5.6)#?
1 Answer
May 26, 2018
Explanation:
#"differentiate using the "color(blue)"chain rule"#
#"given "y=f(g(x))" then"#
#dy/dx=f'(g(x))xxg'(x)larrcolor(blue)"chain rule"#
#d/dx(cos(x^5.6))#
#=-sin(x^5.6)xxd/dx(x^5.6)#
#=-5.6x^4.6sin(x^5.6)#
