# How do you differentiate 3(x^2-2)^4?

It is $24 x \cdot {\left({x}^{2} - 2\right)}^{3}$
We set $f \left(x\right) = 3 \cdot {\left({x}^{2} - 2\right)}^{4}$ hence the derivative is
$\frac{d \left(f \left(x\right)\right)}{\mathrm{dx}} = 12 \cdot {\left({x}^{2} - 2\right)}^{3} \cdot \left(2 x\right) = 24 x \cdot {\left({x}^{2} - 2\right)}^{3}$