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How do you differentiate #3(x^2-2)^4#?

1 Answer

Apr 6, 2018

#(dz)/(dx)=24x(x^2-2)^3#

Explanation:

#u=x^2-2#

#z=3(u)^4#

#u=x^2-2#

#(du)/dx=2x#

#Z=3(u)^4#

#(dz)/(du)=12u^3#

we need #(dz)/(dx)#

#(du)/dxxx(dz)/(du)#

#(dz)/(dx)=24x(x^2-2)^3#

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