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How do you differentiate #2^(2x)#?

1 Answer

Apr 17, 2016

#d/dx = 2^(2x) ln 2 *2#

#=2^(2x+1) ln 2#

Explanation:

Use formula #b^u= b^u ln b xx u'#

#d/dx = 2^(2x) ln 2 *2#

#=2*2^(2x) ln2#

#=2^(2x+1) ln 2#

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