How do you determine the standard form of the equation of the line that passes through (-7,8) and (0,2)?

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Answer 1 · 2017-01-21T08:42:24

#7y+6x-14=0#.

If we know two coordinates of a line

#(x_1,y_1),(x_2,y_2)#

then the eqn can be found using the formula;

#(y-y_1)/(y_2-y_1)=(x-x_1)/(x_2-x_1)#

in this case:

#(x_1,y_1)=(-7,8)#

#(x_2,y_2)=(0,2)#

so: #(y-8)/(2-8)=(x--7)/(0--7)#

#(y-8)/-6=(x+7)/7#

#=>7y-56=-6x-42#

#7y+6x-14=0#.