How do you determine the standard form of the equation of the line that passes through (-7,8) and (0,2)?

Question

2376 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-01-21T08:42:24

$7y+6x-14=0$ .

If we know two coordinates of a line

$(x_1,y_1),(x_2,y_2)$

then the eqn can be found using the formula;

$(y-y_1)/(y_2-y_1)=(x-x_1)/(x_2-x_1)$

in this case:

$(x_1,y_1)=(-7,8)$

$(x_2,y_2)=(0,2)$

so: $(y-8)/(2-8)=(x--7)/(0--7)$

$(y-8)/-6=(x+7)/7$

$=>7y-56=-6x-42$

$7y+6x-14=0$ .