How do you determine #(dy)/(dx)# given #y=cos(1-x)#?
1 Answer
Mar 10, 2017
Explanation:
differentiate using the
#color(blue)"chain rule"#
#"Given "y=cos(g(x))" then"#
#color(red)(bar(ul(|color(white)(2/2)color(black)(dy/dx=-sin(g(x)).g'(x))color(white)(2/2)|)))#
#rArrdy/dx=-sin(1-x)xxd/dx(1-x)#
#color(white)(rArrdy/dx)=sin(1-x)#
