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How do you determine #(dy)/(dx)# given #f(x)=(3x^4-7)^10#?

1 Answer

Aug 10, 2016

#f'(x)=120x^3(3x^4-7)^9#

Explanation:

#f(x)= (3x^4-7)^10#

#f'(x) = 10(3x^4-7)^9 * d/dx(3x^4-7)# (Power rule and Chain rule)

#= 10(3x^4-7)^9 * (12x^3 -0)# (Power rule)

#= 120x^3(3x^4-7)^9#

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