How do you determine #(dy)/(dx)# given #f(x)=(3x^4-7)^10#? Calculus Basic Differentiation Rules Chain Rule 1 Answer Alan N. Aug 10, 2016 #f'(x)=120x^3(3x^4-7)^9# Explanation: #f(x)= (3x^4-7)^10# #f'(x) = 10(3x^4-7)^9 * d/dx(3x^4-7)# (Power rule and Chain rule) #= 10(3x^4-7)^9 * (12x^3 -0)# (Power rule) #= 120x^3(3x^4-7)^9# Answer link Related questions What is the Chain Rule for derivatives? How do you find the derivative of #y= 6cos(x^2)# ? How do you find the derivative of #y=6 cos(x^3+3)# ? How do you find the derivative of #y=e^(x^2)# ? How do you find the derivative of #y=ln(sin(x))# ? How do you find the derivative of #y=ln(e^x+3)# ? How do you find the derivative of #y=tan(5x)# ? How do you find the derivative of #y= (4x-x^2)^10# ? How do you find the derivative of #y= (x^2+3x+5)^(1/4)# ? How do you find the derivative of #y= ((1+x)/(1-x))^3# ? See all questions in Chain Rule Impact of this question 1686 views around the world You can reuse this answer Creative Commons License