How do you describe the nature of the roots of the equation $3x^2-4x=-2$ ?

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Answer 1 · 2016-08-29T09:49:35

The roots are imaginary / non-real.
The equation cannot be solved.

Work with $3x^2 -4x+2 =0$

Find the discriminant. $Delta = b^2 -4ac$

$Delta = (-4)^2 - 4(3)(2)$
$Delta = 16-24$
$Delta = -8$

$Delta < 0$

The roots are imaginary / non-real
(They do not exist, so there are no real solutions to this equation).

How do you describe the nature of the roots of the equation 3x^2-4x=-23x^2-4x=-2?