How do you convert #theta=(2pi)/3# into cartesian form?

1 Answer
Alan P.
Nov 4, 2016

#y=-1/sqrt(3)x#

Explanation:

As per the diagram below using a unit circle
#color(white0("XXX") theta=(2pi)/3#

Gives a slope of #(1/2)/(-sqrt(3)/2)= -1/sqrt(3)#enter image source here

Using the slope-intercept form
#color(white)("XXX")y=color(blue)mx+color(red)b#
with slope #color(blue)(m=-1/sqrt(3))#
and y-intercept #color(red)(b=0)#

gives #y=color(blue)(-1/sqrt(3)x +color(red)0#

Related questions
See all questions in Converting Equations from Polar to Rectangular
Impact of this question
5738 views around the world
You can reuse this answer
Creative Commons License