How do I convert the polar equation #r=10# to its Cartesian equivalent? Precalculus Polar Coordinates Converting Equations from Polar to Rectangular 1 Answer AJ Speller Oct 2, 2014 #r=10# #sqrt(x^2+y^2)=10# square both sides #(sqrt(x^2+y^2))^2=10^2# #x^2+y^2=100# Answer link Related questions What is the polar equation of a horizontal line? What is the polar equation for #x^2+y^2=9#? How do I graph a polar equation? How do I find the polar equation for #y = 5#? What is a polar equation? How do I find the polar equation for #x^2+y^2=7y#? How do I convert the polar equation #r=10 sin theta# to its Cartesian equivalent? How do you convert polar equations to rectangular equations? How do you convert #r=6cosθ# into a cartesian equation? How do you convert #r^2 = 4 sin θ# into a cartesian equation? See all questions in Converting Equations from Polar to Rectangular Impact of this question 6701 views around the world You can reuse this answer Creative Commons License