How do you condense #lny-2ln(x-2)+3 #?

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How do you condense #lny-2ln(x-2)+3 #?

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Answer 1 · 2016-04-02T17:09:04

#ln ((e^3y)/(x-2)^2)#

Explanation:

Exp and ln are inverse functions.#. ln (e^m)=m#.
So, #3 = ln (e^3)#.
#-2 ln (x-2)=ln((x-2)^(-2))#.
Use lna + ln b = ln c = ln (abc)
The given expression condenses to #ln ((e^3y)/(x-2)^2)#

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How do you condense #lny-2ln(x-2)+3 #?

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