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How do you condense #7lnx-2lny #?

1 Answer

Shwetank Mauria

Mar 28, 2016

#ln(x^7/y^2)#

Explanation:

We may use the identities #lna-lnb=ln(a/b)# and #alnb=lna^b#.

Using them #7lnx-2lny#

= #lnx^7-lny^2#

= #ln(x^7/y^2)#

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