How do you condense 7lnx-2lny ?

Mar 28, 2016

$\ln \left({x}^{7} / {y}^{2}\right)$

Explanation:

We may use the identities $\ln a - \ln b = \ln \left(\frac{a}{b}\right)$ and $a \ln b = \ln {a}^{b}$.

Using them $7 \ln x - 2 \ln y$

= $\ln {x}^{7} - \ln {y}^{2}$

= $\ln \left({x}^{7} / {y}^{2}\right)$