How do you condense 4[lnz+ln(z+5)2ln(z5)]?

1 Answer
Jul 2, 2018

4ln(z(z+5)(z5)2)

Explanation:

We have the following:

4(lnz+ln(z+5)2ln(z5))

Recall the logarithm/natural log rule

lna+lnb=ln(ab)

This allows us to rewrite the blue terms as

4(ln(z(z+5))2ln(z5))

We can reference another logarithm/natural log rule:

alogcb=logc(ba)

We can apply this to the purple term. Our coefficient simply becomes our exponent. We now have

4(ln(z(z+5))ln(z5)2)

We can leverage yet another logarithm/natural log rule:

logcalogcb=logc(ab)

If we have the same base and we're subtracting, we can turn this into division. We now have

4ln(z(z+5)(z5)2)

Hope this helps!