How do you complete each ordered pair (4, _) so that it is a solution to 6x - y = 7?

1 Answer
Alan P.
May 12, 2016

#(4,color(blue)(17))#

Explanation:

Let the missing value be #k#
so that #(4,k)# is a solution to the equation
#color(white)("XXX")6x-y=7#

Substituting #(4,k)# for #(x,y)# (i.e. #4# for #x# and #k# for #y#)
we get
#color(white)("XXX")6*(4)-k=7#

#color(white)("XXX")24-y=7#

#color(white)("XXX") y=17#

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