How do you add $sqrt32+9sqrt2-sqrt18$ ?

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Answer 1 · 2016-04-29T03:03:16

$sqrt32+9sqrt2-sqrt18=10sqrt2$

$sqrt32+9sqrt2-sqrt18$

= $sqrt(ul(2xx2xx2xx2)xx2)+9sqrt2-sqrt(ul(3xx3)xx2)$

= $2xx2xxsqrt2+9sqrt2-3sqrt2$

= $4sqrt2+9sqrt2-3sqrt2$

= $(4+9-3)sqrt2$

= $10sqrt2$

How do you add sqrt32+9sqrt2-sqrt18sqrt32+9sqrt2-sqrt18?