How do I integrate $f(x)=(x^3e^(2x))/(x^2 +1)^2$ by parts?

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Answer 1 · 2015-03-28T00:52:25

Wolfram Alpha gives an answer of
$1/2[(1+i)e^(2i)Ei(2x-2i)+(1-i)e^(-2i)Ei(2x+2i)+(e^2x)/(x^2+1)]+C$

Good luck.

How do I integrate f(x)=(x^3e^(2x))/(x^2 +1)^2f(x)=(x^3e^(2x))/(x^2 +1)^2 by parts?