How do I find the derivative of #f(x)=pi^cosx#? Calculus Basic Differentiation Rules Chain Rule 1 Answer Massimiliano Jan 29, 2015 The answer is: #y'=pi^cos(x)ln(pi)(-sin(x))# using the formula: #y=a^f(x)rArry'=a^f(x)ln(a)f'(x)# Answer link Related questions What is the Chain Rule for derivatives? How do you find the derivative of #y= 6cos(x^2)# ? How do you find the derivative of #y=6 cos(x^3+3)# ? How do you find the derivative of #y=e^(x^2)# ? How do you find the derivative of #y=ln(sin(x))# ? How do you find the derivative of #y=ln(e^x+3)# ? How do you find the derivative of #y=tan(5x)# ? How do you find the derivative of #y= (4x-x^2)^10# ? How do you find the derivative of #y= (x^2+3x+5)^(1/4)# ? How do you find the derivative of #y= ((1+x)/(1-x))^3# ? See all questions in Chain Rule Impact of this question 2051 views around the world You can reuse this answer Creative Commons License