Hey, if anybody it would be great and show work thanks. $3 x^{3} + 15 x^{2} - 12 x^{2} - 60 x$ $3x^3+15x^2-12x^2-60x$ . ?

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Hey, if anybody it would be great and show work thanks. $3 x^{3} + 15 x^{2} - 12 x^{2} - 60 x$ $3x^3+15x^2-12x^2-60x$ . ?

factor by grouping

2 Answers

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Answer 1 · 2017-04-13T18:48:48

Assuming the questioner wants solutions to $3 x^{3} + 15 x^{2} - 12 x^{2} - 60 x = 0$ $3x^3+15x^2-12x^2-60x=0$ , the method is as follows.

Explanation:

$3 x^{3} + 3 x^{2} - 60 x = 0$ $3x^3+3x^2-60x=0$

$x (3 x^{3} + 3 x - 60) = 0$ $x(3x^3+3x-60)=0$

$x = 0$ $x=0$

$3 x^{2} + 3 x - 60 = 0$ $3x^2+3x-60=0$

$x = \frac{- 3 \pm \sqrt{9 - 4 (3) (- 60)}}{2 (3)} = \frac{- 3 \pm \sqrt{729}}{6} = \frac{- 3 \pm 27}{6}$ $x=(-3+-sqrt(9-4(3)(-60)))/(2(3))=(-3+-sqrt729)/6=(-3+-27)/6$

$x = - 5, 4$ $x=-5, 4$

$x_{1} = 0$ $x_1=0$

$x_{2} = 4$ $x_2=4$

$x_{3} = - 5$ $x_3=-5$

Answer 2 · 2017-04-13T21:00:57

The factors are $3 x (x + 5) (x - 4)$ $3x(x+5)(x-4)$

Explanation:

From the terms in the expression, it is possible that the question is to find the factors of the expression.

We can group the four factors into two pairs:

$(3 x^{3} + 15 x^{2}) + (- 12 x^{2} - 60 x) \leftarrow$ $(3x^3 +15x^2 ) + (-12x^2 -60x)" "larr$ common factors

$= 3 x^{2} (x + 5) - 12 x (x + 5) \leftarrow$ $=3x^2(x+5)-12x(x+5)"larr$ common factor and bracket

$= 3 x (x + 5) (x - 4)$ $=3x(x+5)(x-4)$

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Hey, if anybody it would be great and show work thanks. $3 x^{3} + 15 x^{2} - 12 x^{2} - 60 x$ $3x^3+15x^2-12x^2-60x$ . ?

factor by grouping

2 Answers

Explanation:

Explanation:

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Science

Math

Humanities

... and beyond

Hey, if anybody it would be great and show work thanks. 3x3+15x2−12x2−60x3x^3+15x^2-12x^2-60x. ?

factor by grouping

2 Answers

Explanation:

Explanation:

Related questions

Impact of this question

Hey, if anybody it would be great and show work thanks. $3 x^{3} + 15 x^{2} - 12 x^{2} - 60 x$ $3x^3+15x^2-12x^2-60x$ . ?