Given the equation $(ax+b)(ax-b)=0$ , how do you solve for x?

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Answer 1 · 2016-12-21T16:17:10

$x=+-b/a$

multiply out and rearrange for $""x$

$(ax+b)(ax-b)$

this is difference of squares

$a^2x^2-b^2=0$

$a^2x^2=b^2$

$x^2=b^2/a^2$

$x=+-sqrt(b^2/a^2$

$x=+-b/a$

Given the equation (ax+b)(ax-b)=0(ax+b)(ax-b)=0, how do you solve for x?