Given right triangle ABC, with right angle at C, if a = 5 and b = 11 use the pythagorean theorem to solve for b?

2 Answers
Jun 12, 2016

Error in question:
If b=11 and we are to solve for color(red)(c) then color(green)(c=sqrt(146)~~12.08305)
If color(red)(c)=11 and we are to solve for b then color(green)(b=4sqrt(6)~~9.797959)

Explanation:

By Pythagorean Theorem (since c is the hypotenuse)
color(white)("XXX")a^2+b^2=c^2

If we are trying to find the value of b, then
color(white)("XXX")b=sqrt(c^2-a^2)

If we are trying to find the value of c, then
color(white)("XXX")c=sqrt(a^2+b^2)

Simply insert whichever values were intended and perform (or have your calculator perform) the arithmetic.

Jun 12, 2016

The question needs to be clarified... b appears twice.
Either:c = 12.08 or b= 9.80 " or4sqrt6

Explanation:

The small letters represent the sides opposite the vertices with the same capital letter.
c would therefore be the hypotenuse.

This would involved squaring and adding the given sides.

c^2 = 5^2 + 11^2 = 25 + 121
If c^2 = 146, " " rArr c = sqrt146
c = 12.08

However, if b=11 is meant to be c = 11, it means we are trying to find one of the shorter sides (b), which would involve subtracting:

b^2 = 11^2 -5^2 = 121 - 25
if b^2 = 96, " " rArr b = sqrt96
b= 9.80 " " or4sqrt6