For the quadratic equation $3 x^{2} - 5 x + 2 = 0$ $3x^2 -5x +2= 0$ . How do you name the larger of the two solutions?

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Answer 1 · 2016-11-29T07:24:34

$x = 1$ $x=1$

Find the factors of the quadratic trinomial first.

$3 x^{2} - 5 x + 2 = 0$ $3x^2 -5x+2=0$

$(3 x - 2) (x - 1) = 0$ $(3x-2)(x-1)=0$

Solve each factor equal to 0.

$3 x - 2 = 0 \to 3 x = 2 \to x = \frac{2}{3}$ $3x-2=0" "rarr 3x=2" "rarr x = 2/3$

$x - 1 = 0 \to x = 1$ $x-1 = 0" "rarr x=1$

Of the two solutions, $x = 1$ $x=1$ is the larger.

For the quadratic equation 3x2−5x+2=03x^2 -5x +2= 0. How do you name the larger of the two solutions?