Differentiate #sinx# #/# #5x# + #sec^2 x"# ?

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Differentiate #sinx# #/# #5x# + #sec^2 x"# ?

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Answer 1 · 2017-06-06T15:01:38

#(xcosx-sinx)/(5x^2)+2sec^2xtanx#

Explanation:

#d/dx(sinx/(5x)+sec^2x)#
#=d/dx(sinx/(5x))+d/dx(sec^2x)#
#=((d(sinx))/dx(5x)-sinx(d(5x))/dx)/(5x)^2+(d(sec^2x))/(dsecx)*(d(secx))/dx#
#=(cosx*5x-5sinx)/(25x^2)+2secx*secxtanx#

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Differentiate #sinx# #/# #5x# + #sec^2 x"# ?

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