How do you find the partial derivative of the function #f(x,y)=intcos(-7t^2-6t-1)dt#?

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How do you find the partial derivative of the function #f(x,y)=intcos(-7t^2-6t-1)dt#?

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Answer 1 · 2015-03-15T17:24:56

You need to be more specific about how #f# depends on #x# and #y#. Are they in the limits of the integral? Are they part of the integrand function? As you wrote it, there's no #x# or #y# dependence on the right-hand side and the derivatives with respect to #x# and #y# would be zero.

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How do you find the partial derivative of the function #f(x,y)=intcos(-7t^2-6t-1)dt#?

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