What is the derivative of #f(x)=1/3sec^3(2x)tan(2x)-2sec(2x)tan(2x)#?
1 Answer
Jul 16, 2017
Explanation:
Evaluate using the chain rule:
#f(x)=1/3sec^3(2x)-sec(2x)#
#f'(x)=1/3(3)sec^2(2x)sec(2x)tan(2x)(2)-sec(2x)tan(2x)(2)#
Simplifying:
#=>f'(x)=2sec^3(2x)tan(2x)-2sec(2x)tan(2x)#
