What is the Lewis structure of sulfur dioxide? And what is #/_O-S-O#?

1 Answer
anor277
Jun 22, 2017

One........

Explanation:

We have #3xx6=18# valence electrons to distribute around three centres; the least electronegative centre, #S#, is placed in the middle.

And we gets....#O=ddotS^(+)-O^(-)#; and around each atom from left to right there are #6,5#, and #7# #"valence electrons"#.........resulting in formal charges of #0,+1,-1#....

#/_O-S-O=119^@#...................

Are the oxygens equivalent?

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