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Question #26561

1 Answer

Jun 17, 2017

You need 27 g of #"NaCl"#.

Explanation:

#"Mass of NaCl" = 180 color(red)(cancel(color(black)("g H"_2"O"))) × "15 g NaCl"/(100 color(red)(cancel(color(black)("g H"_2"O")))) = "27 g NaCl"#

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