What is the percent concentration of a 6m solution of NaCl?

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What is the percent concentration of a 6m solution of NaCl?

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Answer 1 · 2014-05-25T20:31:24

A 6 mol/L solution is 30 % by mass.

Percent by mass = $\frac{Mass of NaCl}{Total mass of solution}$ $"Mass of NaCl"/"Total mass of solution"$ × 100 %

Let's assume that we have 1 L of the solution.

Calculate Mass of NaCl

Mass of NaCl = 1 L soln × $\frac{6 mol NaCl}{1 L soln} \times \frac{58.44 g NaCl}{1 mol NaCl}$ $(6" mol NaCl")/(1" L soln") × (58.44" g NaCl")/(1" mol NaCl")$ = 400 g NaCl.

Calculate Mass of Solution

To get the mass of the solution, we must know its density. I will assume that density = 1.2 g/mL.

Mass of solution = 1000 mL × $\frac{1.2 g}{1 mL}$ $(1.2" g")/(1" mL")$ = 1200 g

Calculate Percent by Mass

Percent by mass = $\frac{Mass of NaCl}{Total mass of solution} \times 100 % = \frac{400 g}{1200 g}$ $"Mass of NaCl"/"Total mass of solution" × 100 % = (400" g")/(1200" g")$ × 100 % = 30 %

Note: I have calculated the answer to only 1 significant figure, because that is all you gave me for the molarity of the NaCl. If you need more precision, you will have to recalculate.

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What is the percent concentration of a 6m solution of NaCl?

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