In which interval the function f(x)=sqrt(x^2+8)-x is a decreasing function?
1 Answer
Apr 4, 2017
Explanation:
Intervals of increasing of a function are those where
Here
and
=x/sqrt(x^2+8)-1
=(x-sqrt(x^2+8))/sqrt(x^2+8)
It is apparent that as
i.e. for all
Hence,
graph{sqrt(x^2+8)-x [-8.125, 11.875, -3.28, 6.72]}